[tex] P(n,k) [/tex] where [tex] n=k [/tex] is equal to [tex] n! [/tex]
So, [tex] P(3,3)=3!=6 [/tex]
Generally, [tex] P(n,k)=\dfrac{n!}{(n-k)!} [/tex]
Answer:
The value of P(3,3) is 6
Step-by-step explanation:
We have to evaluate P(3,3)
As permutation can be calculated by the formula
[tex]P(n,r)=_r^n\txterm{P}=\frac{n!}{(n-r)!}[/tex]
[tex]P(3,3)=_3^3\txterm{P}=\frac{3!}{(3-3)!}[/tex]
[tex]=\frac{3!}{0!}=\frac{3!}{1}=3\times 2\times 1=6[/tex]
Hence, the value of P(3,3) is 6
