Answer :

Answer:

[tex]x=\frac{-3\pm\sqrt{(3)^2-4(5)(-4)}}{2(5)}[/tex]

Therefore, Option 1 is correct.

Step-by-step explanation:

We have been given the quadratic equation:

[tex]5x^2+3x-4=0[/tex]

If we compare it will general quadratic equation which is: [tex]ax^2+bx+c=0[/tex]

Here, a=5,b=3 and c= -4.

Now, we will use the formula:

And then [tex]x=\frac{-b\pm\sqrt{D}}{2a}[/tex]

Where,[tex]D=b^2-4ac[/tex]

[tex]x=\frac{-3\pm\sqrt{(3)^2-4(5)(-4)}}{2(5)}[/tex]

Therefore, Option 1 is correct.

adioabiola

The equation which shows the quadratic formula used correctly to solve 5x² + 3x – 4 = 0 for x is Choice A.

The quadratic equation typically takes the form;

  • ax² + bx + c = 0.

The quadratic formula used to solve for x in the quadratic equation above is given as;

  • x = {-b ± √(b² - 4ac)}/2a.

By comparison with the equation; 5x² + 3x - 4 = 0.

We have;

  • a = 5

  • b = 3

  • c = -4.

To write the quadratic formula used correctly to solve 5x² + 3x- 4 for x yields;

  • x = {-3 ± √(3²) - 4(5) × (-4)} / 2(5).

Evidently, only Choice A looks the exact same way as the formula above.

Read more:

https://brainly.com/question/11865494

Other Questions