Answer:
a. [tex]\frac{1}{4}[/tex]
Step-by-step explanation:
We are asked to find the probability of getting 3 heads on 4 flips.
[tex]\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}[/tex]
Since we know that flipping a fair coin has 2 equally likely possible outcomes, so flipping four coins will have [tex]2*2*2*2=16[/tex] possible outcomes.
Sample space of possible outcomes.
HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT,
THHH, THHT, THTH,THTT, TTHH, TTHT, TTTH, TTTT.
We can see that there are 4 favorable outcomes of getting heads.
[tex]\text{Probability of getting 3 heads}=\frac{4}{16}[/tex]
[tex]\text{Probability of getting 3 heads}=\frac{1}{4}[/tex]
Therefore, the probability of getting 3 heads on 4 coins will be [tex]\frac{1}{4}[/tex] and option a is the correct choice.