Adith
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Please solve this sum. Thanks in Advance...
[tex]( {5}^{2x} \times 5 ) \div ( {5}^{3x - 2}) = ( {25})^{ - 2} [/tex]
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Answer :

Answer:

Step-by-step explanation:

(5^2x*5^1)÷(5^3x-2)=(25)^-2

(5^2x+1)÷(5^3x-2)=(5)^-4

(5^-x+3)=5^-4

-x+3=-4

x=7

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