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in chickens, black feathers are dominant to white feathers. create a punnett square for a cross between two chickens that have both black and white feathers. then list the phenotypic and genotypic ratios of offspring

Answer :

the offspring has a 50% chance of having black feathers and a 50% chance of white feathers

In codominance, the phenotype of Heter0zyg0us individuals results in the additive expression of both alleles. Genotypic ratio: 1:2:1 → 1/4 BB, 2/4 BW, 1/4 WW. Phenotypic ratio: 1:2:1 → 1/4 black, 2/4 speckled, 1/4 white.

What is co-dominance?

Codominance refers to those cases in which a phenotype expresses two alternative variants inherited from each h0m0zyg0us parent.

When two individuals, who are h0m0zyg0us and different for a trait, are crossed they produce heter0zyg0us individuals. In codominance, these Heter0zyg0te individuals express both alleles.

Heter0zyg0us individuals' phenotype is the additive expression of their parent's genes. Both alleles are equally expressed.

A typical example of codominance is the case of speckled chicken.

Speckled chickens (BW) are the product of the cross of a black individual (BB) with a white individual (WW). Their progeny will express both genes as speckled feathers.

In the exposed example we need to cross two individuals that express both colors, meaning they are heter0zyg0us.

Cross) Two speckled individuals

Parentals)  BW   x   BW

Gametes) B   W     B   W

Punnett square)    B       W

                     B    BB     BW

                     W   BW    WW

F1) 1/4 = 25% of the progeny is expected to be h0m0zygous dominant, expressing black feathers ⇒ BB

    2/4 = 50% of the progeny is expected to be heter0zyg0us, expressing speckled feathers ⇒ Bb

    1/4 = 25% of the progeny is expected to be h0m0zyg0us recessive expressing white feathers ⇒ bb

Genotypic ratio ⇒ 1:2:1 → 1/4 BB, 2/4 BW, 1/4 WW

Phenotypic ratio ⇒ 1:2:1 → 1/4 black, 2/4 speckled, 1/4 white

You will learn more about codominance at

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