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what is an equation of the line that is perpendicular to y+1-3x-5 and passes through the point 4,-6

Answer :

MrsStrong

Answer:

[tex]y + 6 = \frac{1}{3}(x-4)[/tex]

Step-by-step explanation:

A perpendicular line is a line whose slope is the negative reciprocal of the other line. The line y + 1 = -3x - 5 has slope -3. This means the line perpendicular will be 1/3.

Substitute 1/3 and (4.-6) into the point slope form of a line.

[tex]y - y_1 = m(x-x_1)\\y --6 = \frac{1}{3}(x - 4)\\y + 6 = \frac{1}{3}(x-4)[/tex]

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