Charge q is 1 unit of distance away from the source charge S. Charge p is four times further away. The force exerted between S and q is _____ the force exerted between S and p.
one0fourth
four times
one0sixteenth
sixteen times

Answer :

skyluke89

The correct answer is:

sixteen times


In fact, the distance between charge q and the source S is 1 unit. Instead, the distance between charge p and the source S is 4 units. The magnitude of the electrostatic force is inversely proportional to the square of the distance between the charge and the source:

[tex] E \sim \frac{1}{r^2} [/tex]

where r is the distance. If we take the force between q and S as reference, we have r=1, so that

[tex] E_{qS}=\frac{1}{1^2}=1 [/tex]

while the force between p and S is

[tex] E_{pS}=\frac{1}{4^2}=\frac{1}{16}[/tex]

Therefore, we see that the force exerted between q and S is 16 times the force exerted between p and S.

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