Answer :
Answer:
151.63 g
Explanation:
We first get the number of moles;
Moles = Molarity × volume
= 2.0 × 0.475
= 0.95 moles
1 mole of CuSO4 = 159.609 g/mol
Therefore;
Mass = moles × molar mas
= 0.95 moles × 159.609 g/mol
= 151.63 g
Answer: The mass of copper sulfate present are 151.63 grams
Explanation:
To calculate the mass of solute, we use the equation used to calculate the molarity of solution:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}[/tex]
We are given:
Molarity of solution = 2.0 M
Molar mass of copper sulfate = 159.61 g/mol
Volume of solution = 475 mL
Putting values in above equation, we get:
[tex]2.0M=\frac{\text{Mass of copper sulfate}\times 1000}{159.61\times 475}\\\\\text{Mass of copper sulfate}=\frac{2.0\times 159.61\times 475}{1000}=151.63g[/tex]
Hence, the mass of copper sulfate present are 151.63 grams