Answer :

gmany

Answer:

[tex]\large\boxed{6.\ 2\left[\begin{array}{ccc}2&3\\1&5\end{array}\right] +\left[\begin{array}{ccc}1&2\\3&4\end{array}\right] =\left[\begin{array}{ccc}5&8\\5&14\end{array}\right] }\\\boxed{7.\ 3^2-4(-2+5)=-3}[/tex]

Step-by-step explanation:

[tex]6.\\2\left[\begin{array}{ccc}2&3\\1&5\end{array}\right] +\left[\begin{array}{ccc}1&2\\3&4\end{array}\right] =\left[\begin{array}{ccc}2\cdot2&2\cdot3\\2\cdot1&2\cdot5\end{array}\right] +\left[\begin{array}{ccc}1&2\\3&4\end{array}\right]\\\\=\left[\begin{array}{ccc}4&6\\2&10\end{array}\right] +\left[\begin{array}{ccc}1&2\\3&4\end{array}\right]=\left[\begin{array}{ccc}4+1&6+2\\2+3&10+4\end{array}\right] \\\\=\left[\begin{array}{ccc}5&8\\5&14\end{array}\right][/tex]

[tex]7.\\3^2-4(-2+5)\qquad\text{use PEMDAS}\\\\=9-4(3)\\\\=9-12\\\\=-3[/tex]

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