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During each cycle, the velocity (v in mm/s) of a piston is v=6t-6t^2, where t is the time in seconds. Find the displacement "s" of the piston after .75 s if the initial displacement is zero.

Answer :

ANSWER

0.84375 mm

EXPLANATION

The velocity function is given by:

[tex]v = 6t - 6 {t}^{2} [/tex]

To find the displacement function, we integrate:

[tex]s = \int \: 6t - 6 {t}^{2}d t[/tex]

[tex]s (t) = 3 {t}^{2} - 2 {t}^{3} + c[/tex]

The initial displacement is zero.

This implies that,

[tex]3 {(0)}^{2} - 2 {(0)}^{3} + c = 0[/tex]

[tex]c = 0[/tex]

This gives us,

[tex]s (t) = 3 {t}^{2} - 2 {t}^{3} [/tex]

After t=0.75s,

[tex]s (0.75) = 3 {(0.75)}^{2} - 2 {(0.75)}^{3} + c[/tex]

[tex]s (0.75) = 0.84375[/tex]

Answer:

the answer is 0.84375 mm

Step-by-step explanation:

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