Answer :
Answer:
0.0032 A
Explanation:
The magnitude of the charge of one electron is
[tex]q=1.6\cdot 10^{-19} C[/tex]
Therefore, if we have a total of
[tex]N=2.0\cdot 10^{13}[/tex] electrons, their total charge would be
[tex]Q=Nq=(2.0\cdot 10^{13})(1.6 \cdot 10^{-19}C)=3.2\cdot 10^{-6} C[/tex]
The current in the transistor is given by
[tex]I=\frac{Q}{t}[/tex]
where
Q is the total charge of the electrons flowing through it
t = 1.0 ms = 0.001 s is the time taken
Substituting into the equation, we find
[tex]I=\frac{3.2\cdot 10^{-6} C}{0.001 s}=0.0032 A[/tex]