Calculate the force experienced by a positive test charge of 8.1 × 10-9 coulombs if the electric field strength is 9.4 × 107 newtons/coulomb.
A.
1.5 × 10-1 newtons
B.
9.4 × 10-7 newtons
C.
7.6 × 10-1 newtons
D.
8.7 × 10-1 newtons

Answer :

skyluke89

Answer:

C.  

7.6 × 10-1 newtons

Explanation:

The electrostatic force experienced by a charge is given by

[tex]F=qE[/tex]

where

q is the magnitude of the charge

E is the magnitude of the electric field

In this problem, we have

[tex]q=8.1\cdot 10^{-9}C[/tex] is the charge

[tex]E=9.4\cdot 10^7 N/C[/tex] is the electric field

Substituting into the formula, we find

[tex]F=(8.1 \cdot 10^{-9} C)(9.4\cdot 10^7 N/C)=0.76 N = 7.6\cdot 10^{-1}N[/tex]

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