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The base of a pyramid is a square with side lengths of 5 centimeters. The slant height of each lateral face of the pyramid is 6 centimeters. What is the surface area of the pyramid? A. 65 cm2 B. 75 cm2 C. 85 cm2 D. 95 cm2 E. 105 cm2

Answer :

the answer is C. 85cm


ok so since you are dealing with a pyramid you know that it has one square and four triangles.
since the base is a square and its side length is 5cm and a square's sides are all equal then you would do 5×5=25 because the area of a square is base times height. and now on to the triangles. since you have four triangles you just need to find the area of one then multiply that area by 4. the area of a triangle is base×height×1/2. so the base is 5 and the height is 6 now you would do 5×6×1/2=15. now do 15×4=60. now you just add the surface areas of the 4 triangles (60) and the square (25) which equals 85. so your answer is 85cm. which is C.

Answer:

Option C. 85 cm² is the answer.

Step-by-step explanation:

The base of a pyramid is a square with side length of 5 cm.

Slant height of the lateral face of the pyramid = 6 cm.

We have to find the surface area of the pyramid.

Surface area of the pyramid = area of base + area of lateral faces.

Area of base = 5² = 25 cm²

Area of one lateral face = [tex]\frac{1}{2}[/tex] (base) (height)

                                       = [tex]\frac{1}{2}[/tex] × 5 × 6 = 15 cm²

Total area of 4 lateral faces = 4 × 15 = 60 cm²

Now surface area of square pyramid = 25 + 60 = 85 cm²

Option C. 85 cm² is the answer.

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