Answered

Triangle XYZ is translated 4 units up and 3 units left to yield ΔX'Y'Z'. What is the distance between any two corresponding points on ΔXYZ and ΔX'Y'Z′

Answer :

calculista

Answer:

The distance between any two corresponding points on ΔXYZ and ΔX'Y'Z′ is equal to [tex]5\ units[/tex]

Step-by-step explanation:

we know that

To find the distance, apply the Pythagoras Theorem

Let

x ----> the distance between any two corresponding points on ΔXYZ and ΔX'Y'Z′

[tex]x=\sqrt{4^{2}+3^{2}} \\ \\x=\sqrt{25}\ units\\ \\x=5\ units[/tex]

poopscooter352

Answer:

5

Step-by-step explanation:

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