Answer :
Answer:
Electric force, [tex]F=2.88\times 10^{-14}\ N[/tex]
Explanation:
It is given that,
Magnitude of electric field, [tex]E=6\times 10^4\ N/C[/tex]
Charge, [tex]q=4.8\times 10^{-19}\ C[/tex]
The electric field is directed parallel to the positive y axis. We need to find the force on the charge particle. It is given by :
[tex]F=q\times E[/tex]
[tex]F=4.8\times 10^{-19}\ C\times 6\times 10^4\ N/C[/tex]
[tex]F=2.88\times 10^{-14}\ N[/tex]
So, the electric force on the charge is [tex]2.88\times 10^{-14}\ N[/tex]. Hence, this is the required solution.