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A container of oxygen with a fixed volume has a pressure of 13.0atm. at temperature of 20 °C what will the pressure of the oxygen be if the container is heated to 102 °C ? A.)12.4atm B.)15.4atm C.) 16.6 atm D.) 18.6atm

Answer :

EjerciciosFyQ
You must follow the Gay-Lussac law of gases but, and this is extremely important, using temperature in Kelvin scale:

[tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}\ \to\ P_2 = \frac{P_1\cdot T_2}{T_1} = \frac{13\ atm\cdot (102 + 273)\ K}{(20 + 273)\ K} = \bf 16.64\ atm[/tex]

The correct answer is C) 16.6 atm.

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