Answer:
5) Cs2O > MgO > SnO2 > P4O10 > Cl2O7
Explanation:
Hello,
In this case, the decreasing basicity order depends on the metal contained into the oxide, in such a way, on the attached picture you will find how the basicity increases leftwards and downwards on the periodic table, as the metallic character does.
In this manner, as the cesium in the Cs₂O is the leftest atom, it is the most basic, next MgO, afterwards SnO₂, then P₄O₁₀ and finally Cl₂O₇, therefore, the order is: 5) Cs₂O> MgO > SnO₂> P₄O₁₀> Cl₂O₇.
Best regards.
The order of decreasing basicity of the compounds listed is; Cs2O > MgO > SnO2 > P4O10 > Cl2O7.
Metals are known to form basic oxides. The oxides of metals react with acids to form salt and water. This is one of the properties of metals.
However, the basicity of metallic oxides decreases across the period. As you go from left to right the metal oxides become less basic. Recall that the oxides of metals are acidic. The react with bases to form salts and water.
The order of decreasing basicity of the compounds listed is; Cs2O > MgO > SnO2 > P4O10 > Cl2O7.
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