Answered

What is the product of the complex number z1 and it’s conjugate? PLEASE HELP GRAPH in picture

What is the product of the complex number z1 and it’s conjugate? PLEASE HELP GRAPH in picture class=

Answer :

calculista

Answer:

The product is 25

Step-by-step explanation:

we know that

The complex number z1 is equal to

z1=(-4-3i)

we know that

To find the complex conjugate of (-4 - 3i) we change the sign of the imaginary part

so

The conjugate is equal to (-4+3i)

therefore

[tex](-4-3i)(-4+3i)=16-9(-1)=25[/tex]

luisejr77

Answer:

[tex](-4-3i) (- 4 + 3i) = 25[/tex]

Step-by-step explanation:

Notice in the graph that z1 has a real component of -4 and an imaginary component of -3.

Then we know that:

[tex]z_1 = -4-3i[/tex]

By definition for an imaginary number of the form [tex]a-bi[/tex] its conjugate will always be the number [tex]a + bi[/tex]

So the conjugate of [tex]z_1[/tex] is:

[tex]-4 + 3i[/tex]

The product of both numbers is:

[tex](-4-3i) (- 4 + 3i) = 16-12i + 12i-9i ^ 2\\\\(-4-3i) (- 4 + 3i) = 16-9 (-1)\\\\(-4-3i) (- 4 + 3i) = 16 + 9\\\\(-4-3i) (- 4 + 3i) = 25[/tex]

Other Questions