Answer :
Answer:
See below in bold.
Step-by-step explanation:
Because one factor is (x + 1), the zero -1 has a multiplicity of 1.
The zero -2 has a multiplicity of 2 because the factor is (x + 2)^2.
For this case we have that by definition, the multiplicity of the root of a polynomial is given by the number of times the root is repeated. Example:
[tex](x-1) ^ n[/tex]
The zero "1" has a multiplicity of "n".
In this case we have the following function:
[tex]f (x) = (x-3) ^ 2 * (x + 2) ^ 2 * (x-1)[/tex]
So:
The zero "3" has a multiplicity of "2".
The zero "-2" has a multiplicity of "2".
The zero "1" has a multiplicity of "1".
Answer:
The zero "1" has a multiplicity of "1".
The zero "-2" has a multiplicity of "2".