solve
set to zero by minusing 6 both sides
x^2+4x-2=0
we can't factor
ok so use quadratic formula
ax^2+bx+c=0
x=[tex] \frac{-b+/- \sqrt{b^{2}-4ac} }{2a} [/tex]
a=1
b=4
c=-2
x=[tex] \frac{-4+/- \sqrt{4^{2}-4(1)(-2)} }{2(1)} [/tex]
x=[tex] \frac{-4+/- \sqrt{16+8} }{2} [/tex]
x=[tex] \frac{-4+/- \sqrt{24} }{2} [/tex]
x=[tex] \frac{-4+/- 2\sqrt{6} }{2} [/tex]
x=[tex] -2+/- \sqrt{6} [/tex]
x=[tex] -2+ \sqrt{6} [/tex] or [tex] -2- \sqrt{6} [/tex]
answer is A and C
