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Suppose a yo-yo has a center shaft that has a 0.232 cm radius and that its string is being pulled. If the string is stationary and the yo-yo accelerates away from it at a rate of 1.50 m/s ​2, what is the angular acceleration of the yo-yo?

Answer :

rokettojanpu
a = Ar
a = linear acceleration of yo-yo, A = angular acceleration, r = radius of yo-yo

Given values:
a = 1.50m/s^2
r = 0.232x10^-2 m

Plug in and solve for A:
1.50 = A(0.232x10^-2)
A = 647rad/s^2

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