Answered

At a certain depth (h) which is one-tenth of its bottom width (h = b/10), a rectangular channel has a velocity of 2 m/s. What will be the velocity in this channel when the depth is doubled?

Answer :

Answer:

The velocity when depth becomes double will be 2.82 m/s

Explanation:

At initial condition

velocity V= 2 m/s

h=b/10

We know that velocity if given as follows for rectangular channel

[tex]V=\sqrt{2gh}[/tex]

Now by putting the values in the above formula

[tex]2=\sqrt{2\times9.81\times h}[/tex]

h=0.203 m

Now when depth is doubled ,it means that new h=2 x 0.203 m

So our new h will be  h=0.406 m

Now again by using formula

[tex]V=\sqrt{2gh}[/tex]

[tex]V=\sqrt{2\times9.81\times 0.406}[/tex]

V=2.82 m/s

So the velocity when depth becomes double will be 2.82 m/s

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