Air enters an adiabatic turbine at 2.8 MPa and 400°C and expands to a lower pressure of 150 kPa. Assume an isentropic efficiency of 90% for the turbine. Determine the actual outlet temperature of the turbine.

Answer :

Answer:

The outlet temperature of turbine is 327.51 K.

Explanation:

We know that

in adiabatic process

[tex]PV^\gamma =C[/tex]

[tex]\dfrac{T_2}{T_1}=\left(\dfrac{P_2}{P_1}\right)^{\frac{\gamma -1}{\gamma }}[/tex]

Now by putting the values

[tex]\dfrac{T_2}{673}=\left(\dfrac{150}{2800}\right)^{\frac{1.4 -1}{1.4 }}[/tex]

[tex]T_2=289.39 K [/tex]

The efficiency of turbine is given as

[tex]\eta =\dfrac{T_1-\acute{T_2}}{T_1-T_2}[/tex]

By putting the values

[tex]0.9=\dfrac{673-\acute{T_2}}{673-289.39}[/tex]

[tex]\acute{T_2}=327.51 K[/tex]

So the outlet temperature of turbine is 327.51 K.

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