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In a certain city, 28% of the population read newspaper A, 22 % read newspaper 8, 15% read newspaper C 13 % read both A and B, 10 % read both A and C, 8 % read B and C, and no one reads all three. If a person from this city is selected at random, what is the probability that he or she does not read any of these newspapers? (b) 0.42 (c) 0.50 (e) 0.66 (a) 0.34 (d) 0.58

Answer :

Answer: Option 'e' is correct.

Step-by-step explanation:

Since we have given that

Probability of the population read newspaper A = 28%

Probability of the population read newspaper B = 22%

Probability of the population read newspaper C = 15%

Probability of the population read A and B = 13%

Probability of the population read B and C = 8%

Probability of the population read A and C = 10%

Probability of the population read A , B and C = 0%

As we know the formula:

P(A∪B∪C)=P(A)+P(B)+P(C)-P(A∩∩B)-P(B∩C)-P(A∩C)+P(A∩B∩C)

[tex]P(A\cup B\cup C)=28+22+15-13-10-8+0=34\%[/tex]

So, the probability that he or she does not read any of these newspapers is given by

[tex]100-34=66\%=0.66[/tex]

Hence, option 'e' is correct.

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