Answer :
Answer:
[tex] \frac{U_{o}}{2}[/tex]
Explanation:
Q = Amount of charge stored by parallel plate capacitor
C₀ = Capacitance of the capacitor
U₀ = Amount of electric potential energy stored
Amount of electric potential energy stored is given as
[tex]U_{o} = \frac{Q^{2}}{2C_{o}}[/tex]
k = dielectric constant of dielectric = 2
New capacitance of the capacitor is given as
C = k C₀
New amount of electric potential energy stored is given as
[tex]U = \frac{Q^{2}}{2C}[/tex]
[tex]U = \frac{Q^{2}}{2 k C_{o}}[/tex]
[tex]U = \frac{U_{o}}{k}[/tex]
[tex]U = \frac{U_{o}}{2}[/tex]