Answered

Nucleus A decays into the stable nucleus B with a half-life of 22.07 s. At t=0 s there are 1,293 A nuclei and no B nuclei. At what time will there be 779 B nuclei?

Answer :

Answer:

29.38 seconds

Explanation:

Half life, T = 22.07 s

No = 1293

Let N be the number of atoms left after time t

N = 1293 - 779 = 514

By the use of law of radioactivity

[tex]N=N_{0}e^{-\lambda t}[/tex]

Where, λ is the decay constant

λ = 0.6931 / T = 0.6931 / 22.07 = 0.0314 decay per second

so,

[tex]514=1293e^{-0.0314t}[/tex]

[tex]2.5155=e^{0.0314t}[/tex]

take natural log on both the sides

0.9225 = 0.0314 t

t = 29.38 seconds

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