Answer :
Answer:
Rate of heat transfer to the room air per meter of pipe length equals 521.99 W/m
Explanation:
Since it is given that the radiation losses from the pipe are negligible thus the only mode of heat transfer will be by convection.
We know that heat transfer by convection is given by
[tex]\dot{Q}=hA(T-T_{\infty })[/tex]
where,
h = heat transfer coefficient = 10.45 [tex]W/m^{2}K[/tex] (free convection in air)
A = Surface Area of the pipe
Applying the given values in the above formula we get
[tex]\dot{Q}=10.45\times \pi DL\times (130+273-(24+273))\\\\\frac{\dot{Q}}{L}=10.45\times 0.15\times \pi \times (130-24)\\\\\frac{\dot{Q}}{L}=521.99W/m[/tex]