Answer :

Answer:

15000N/m

Explanation:

Given Force F=150 N

compressed distance = 0.010 m

We know that force on a spring due to to compression or elongation is given by [tex]F=kx[/tex] here k is force constant and x is compressed or elongated distance

We have to find force constant

So [tex]F=kx=k\times 0.010[/tex]

[tex]k=\frac{150}{0.010}=15000N/m[/tex]

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