Answer :
Answer:
5.65×10⁻²¹ Joules
Explanation:
k = Boltzmann constant = 1.38 × 10⁻²³ m² kg/s² K
t = Temperature of Nitrogen molecule = 1.88×10⁻⁵ °C = 0.0000188 + 273 K = 273.0000188 k
According to Kinetic theory of gases
[tex]E=\frac{3}{2}kt\\\Rightarrow E=\frac{3}{2}1.38\times 10^{-23}\times 273.0000188\\\Rightarrow E=5.65\times 10^{-21}\ Joules[/tex]
∴ Average kinetic energy of a nitrogen molecule is 5.65×10⁻²¹ Joules