Answer :
Answer:
C...90
Explanation:
Energy stored = 1/2 of(Charge × Voltage)
....then substitute Voltage with (Charge ÷ Capacitance)
Then obtain the formula for energy stored as....
E = 1/2 of (Charge)^2 ÷ Capacitance
= 0.5 x (60^2÷20)
;Energy stored = 90
C) 90 μJ
As
Energy stored = 1/2 of(Charge × Volt)
Substitute Volt with (Charge/Capacitance)
Then obtain the formula for energy stored as
W= 1/2 *(Charge)^2 /Capacitance
= 0.5 x (60^2/20)
Energy stored = 90 μJ
Energy stored in a capacitor
The energy stored in the capacitor is equal to the work that is turned into the charge in the capacitor.
If the voltage at any on the spot "v", and a small amount of charge δq is transferred at this voltage, then the work finished will be v δq.
Hence the total work done, and accordingly, the energy stored in the capacitor will be:
W=∫Q0V dQ
From this
W=∫Q0qC dQ
After this
W=1/2CV^2
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