Answer :
Answer:
2.49 V.
Explanation:
The formula which relates the equilibrium condition in the electrochemical cell is,
[tex]logk_{eq}=\frac{n}{0.059} E_{cell} ^{0}[/tex]
Given that the number of electron is 3 and the value of [tex]E^{0} _{cell}[/tex] is 0.652 V.
Now put these values in above equation.
[tex]logk_{eq}=\frac{3}{0.059} (0.652 V)\\logk_{eq}=33.15 V\\k_{eq}=e^{33.15}V\\k_{eq}=2.49V[/tex]
Therefore, the value of Keq for an electrochemical reaction is 2.49 V.