Answer:
Step-by-step explanation:
When adding or subtracting rational expressions, it is easiest to find a common denominator.
Ex.
[tex]\frac{x+2}{x-5} + \frac{x-7}{x} \\[/tex]
The common denominator would be [tex]x(x-5)[/tex]
We need to make both fractions have that denominator
[tex]\frac{(x+2)(x)}{(x-5)x} + \frac{(x-7)(x-5)}{x(x-5)} \\\frac{(x^2+2x)+(x^2-12x+35)}{(x^2-5x)}\\\frac{2x^2-10x+35}{(x^2-5x)}[/tex]
