Answer :
Answer:
[tex]F=2.04\times 10^{-10} N[/tex]
Explanation:
Given that
[tex]q_1=1\times 1.6\times 10^{-19}[/tex]
[tex]q_2=2\times 1.6\times 10^{-19}[/tex]
r= 1.5 nm
We know that force between two charge given as follows
[tex]F=K\dfrac{q_1q_2}{r^2}[/tex]
Where K is the constant
Noe by putting the values
[tex]q_1\times q_2=2\times 1.6\times1.6\times 10^{-38}[/tex]
[tex]F=8.98\times 10^9 \times \dfrac{5.12\times 10^{-38}}{\left ( 1.5\times10^{-9} \right )^2}[/tex]
[tex]F=2.04\times 10^{-10} N[/tex]