Answer :

sqdancefan

Answer:

  [tex]4(x-2)(x-1)^3(x+1)\sqrt{x-1}[/tex]

Step-by-step explanation:

[tex]4x(x-1)^{9/2}-8(x-1)^{7/2}=4(x-1)^{7/2}(x(x-1)^{2/2} -2)=4(x-1)^{7/2}(x^2-x-2)\\\\=4(x-1)^{7/2}(x-2)(x+1)=4(x-2)(x-1)^3(x+1)\sqrt{x-1}[/tex]

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Among other things, the leading coefficient cannot be 2, as 4 is a factor of both the given terms.

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