The density of air at ordinary atmospheric pressure and 25 ∘C is 1.19 g/L. What is the mass, in kilograms, of the air in a room that measures 11.5 × 18.5 × 9.0 ft?

Answer :

Answer:

The mass in kilograms is 64.52

Explanation:

We know that density of a substance is an intensive property that can be calculated with following formula: [tex][tex]density= \frac{mass}{volume} [/tex][/tex]

Using the formula and using simple 3 rule, we can calculate the mass in the room.

First we calculate the volume of the room:

[tex][tex]Volume=lenght*height*with[/tex]\\[tex]Volume=11.5 feet * 18.5 feet *9.0 feet[/tex]\\[tex]Volume=1914.75 feet^{3} [/tex][/tex]

As density is given in grams/liters, we need to change unit measure feet3 to liters:

[tex][tex]1 ft^{3} ---------28.32L\\ 1914.75ft^{3} -----------------------54225.72 L[/tex][/tex]

Now we can use density formula isolating the mass, to get the value needed:

[tex][tex]mass=density*volume[/tex]\\[/tex]

Following step is to replace density and volume with the data that we have:

[tex][tex]mass=1.19g/L*54225.72L\\ mass=64528,60g[/tex][/tex]

We know that 1000 g is 1Kg, so to obtain the value in Kg we need to divide the result.

[tex][tex]mass=64.52Kg[/tex][/tex]

Other Questions