Answer :
Answer:
(a) 80.36 m/s^2
(b) 0.0933 second
Explanation:
initial velocity, u = 7.5 m/s
final velocity, v = 0 m/s
distance moved, s = 0.350 m
(a) Let a be the deceleration.
Use third equation of motion
[tex]v^{2}=u^{2}+2\times a\times s[/tex]
[tex]0^{2}=7.5^{2}+2\times a\times 0.350[/tex]
a = 80.36 m/s^2
Thus, the deceleration is 80.36 m/s^2.
(b) Let the time taken is t
Use first equation of motion
v = u + a t
0 = 7.5 + 80.36 x t
t = 0.0933 second