A pellet of Zn of mass 10.0g is dropped into a flaskcontaining
dilute H2SO4 at a pressure of P=1.00 bar and
temperature of 298K. What is the reaction thatoccures? Calculate w
for the process.

Answer :

Answer: Work done for the process is -390 J

Explanation:

The chemical equation for the reaction of zinc metal with sulfuric acid follows:

[tex]Zn+H_2SO_4\rightarrow ZnSO_4+H_2[/tex]

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given mass of zinc = 10.0 g

Molar mass of zinc = 65.38 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of zinc}=\frac{10.0g}{65.38g/mol}=0.153mol[/tex]

The equation given by ideal gas follows:

[tex]P\Delta V=nRT[/tex]

where, P = pressure of the gas

[tex]\Delta V[/tex] = Change in volume of the gas

T = Temperature of the gas = 298 K

R = Gas constant = 8.314 J/mol.K

n = number of moles of gas = 0.153 mol

Putting values in above equation, we get:

[tex]P\Delta V=0.153mol\times 8.314J/mol.K\times 298K\\\\P\Delta V=397J[/tex]

To calculate the work done, we use the equation:

[tex]\text{Work done}=-P\Delta V\\\\W=-390J[/tex]

Hence, work done for the process is -390 J

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