Answered

A circular loop of wire has an area of 0.27 m^2 . It is tilted by 45° with respect to a uniform 0.38T magnetic field. What is the magnetic flux through the loop?

Answer :

Answer:

The magnetic flux is 0.0725 Wb

Solution:

Area of the wirer, [tex]A_{w} = 0.27 m^{2}[/tex]

Magnetic field associated with the wire, B = 0.38 T

Angle with the magnetic field, [tex]\theta = 45^{\circ}[/tex]

Now, we know that the magnetic flux is given by:

[tex]\phi_{w} = \vec{B}.\vec{A_{w}}[/tex]

[tex]\phi_{w} = BA_{w}cos\theta[/tex]

Now, using the above eqn:

[tex]\phi_{w} = 0.38\times 0.27cos45^{\circ}[/tex]

[tex]\phi_{w} = 0.38\times 0.27cos45^{\circ} = 0.0725 Wb[/tex]

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