Answer :
Answer:
the vertical height reached by the puck is 580.47 m
Explanation:
given,
mass of hockey puck = 200 g
angle of inclination (θ )= 30°
μs = 0.40
μk = 0.30
initial velocity = 93 m/s
acceleration of pluck upwards,
a = - g (cosθ × μk +sin θ)
a = - 9.81 × (0.3 × cos 30° +sin 30°)
a = -7.45 m/s²
now,
s = [tex]\dfrac{u^2}{2a}[/tex]
s = [tex]\dfrac{93^2}{2\times 7.45}[/tex]
s = 580.47 m
the vertical height reached by the puck is 580.47 m