Answer:
[tex]y> \frac{2}{3}x+3[/tex]
Step-by-step explanation:
we have the points
(-3,1) and (0,3)
step 1
Find the slope m of the line
The formula to calculate the slope between two points is equal to
[tex]m=\frac{y2-y1}{x2-x1}[/tex]
substitute the values
[tex]m=\frac{3-1}{0+3}[/tex]
[tex]m=\frac{2}{3}[/tex]
step 2
Find the equation of the line in slope intercept form
[tex]y=mx+b[/tex]
we have
[tex]m=\frac{2}{3}[/tex]
[tex]b=3[/tex] ----> the y-intercept is the point (0,3)
substitute the values
[tex]y=\frac{2}{3}x+3[/tex]
step 3
Find the equation of the inequality
we know that
The slope is positive
Everything to the left of the line is shaded ( The inequality is of the form y > ax+b or y ≥ ax+b)
Is a dashed line (The inequality is of the form y > ax+ b or y < ax+b)
therefore
The equation of the inequality is of the form y > ax+b
The inequality is
[tex]y> \frac{2}{3}x+3[/tex]
see the attached figure to better understand the problem
Answer:
the correct answer is y>2x+(3/4) and (2,5)
hope this helps
(p.s:Please mark me as brainlyest)
Step-by-step explanation:
I just took the test on E2020
