Answer :
Answer:
v = 4.6275 m^3/kg
u = 2217.215 kJ/kg
h = 2356.0105 kJ/kg
Explanation:
Given data:
From steam table
At 30 Kpa
vf = 0.001022 m^3/kg vg = 5.2287 m^3/kg
uf = 289.24 kJ/kg ufg = 2178.5 kJ/kg
hf = 289.27 kJ/kg hfg = 2335.3 kJ/kg
sf = 0.9441 kJ/kg K sfg = 6.8234 kJ/kg K
we know specific heat is given as
[tex]s = sf + x\times sfg[/tex]
[tex]6.983 = 0.9441 + x\times 6.8234[/tex]
x = 0.885
[tex]v = vf + x(vg -vf)[/tex]
[tex]v = 0.001022 + 0.885\times(5.2287-0.001022)[/tex]
v = 4.6275 m^3/kg
[tex]u = uf +x\times ufg[/tex]
[tex]u = 289.24 + 0.885\times 2178.5[/tex]
u = 2217.215 kJ/kg
[tex]h = hf +x\times hfg[/tex]
[tex]h = 289.27 + 0.885\times 2335.3[/tex]
h = 2356.0105 kJ/kg