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A group of students observes that a wooden block (m = 0.40 kg) on the end of a string with a radius of 0.7 meters makes 14 rotations in 20.7 seconds when twirled. Part A Calculate the centripetal acceleration of the wooden block: a = 2.55 m s2 Submit Previous Answer Request Answer Incorrect; Try Again; 4 attempts remaining Part B Calculate the tension in the string acting on the wooden block: TT = 1.02N

Answer :

Answer:

1.02 N

Explanation:

mass of block, m = 0.40 kg

radius, r = 0.7 m

14 rotations in 20.7 second

Centripetal acceleration, a = 2.55 m/s^2

The tension in the string is same as the centripetal force

T = mass x centripetal acceleration

T = 0.4 x 2.55 = 1.012 N

hamzaahmeds

This question involves the concept of centripetal acceleration and centripetal force.

A. The centripetal acceleration of the wooden block is "12.6 m/s²".

B. The tension in string acting on the wooden block is "5.04 N".

A.

The centripetal acceleration of the block can be given by the following formula:

[tex]a=\frac{v^2}{r}[/tex]

where,

a = centripetal aceleration = ?

r = radius = 0.7 m

ω = angular speed = [tex]\frac{14\ rotations}{20.7\ s}(\frac{2\pi\ rad}{1\ rotation})=4.25\ rad/s[/tex]

v = linear speed = rω = (0.7 m)(4.25 rad/s) = 2.97 m/s

Therefore,

[tex]a=\frac{(2.97\ m/s)^2}{0.7\ m}[/tex]

a = 12.6 m/s²

B.

Now the tension in string will be equal to the centripetal force:

T = Centripetal Force

T = ma = (0.4 kg)(12.6 m/s²)

T = 5.04 N

Learn more about centripetal force here:

brainly.com/question/11324711?referrer=searchResults

The attached picture shows the centripetal force.

${teks-lihat-gambar} hamzaahmeds

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