Answer:
a) 4.235 V
b) 3.529 A and 26.471 A
Explanation:
If I₁ is the current in the 1.2Ω cable, and I₂ is the current in the 0.16Ω cable, then the total current is:
I₁ + I₂ = 30
And the voltage drop is the same for each cable:
V = V
IR = IR
1.2 I₁ = 0.16 I₂
Two equations, two variables. Solve with substitution or elimination (I'll use substitution):
1.2 I₁ = 0.16 (30 − I₁)
1.2 I₁ = 4.8 − 0.16 I₁
1.36 I₁ = 4.8
I₁ = 3.529 A
I₂ = 26.471 A
Therefore, the voltage drop is:
V = 1.2 I₁ = 0.16 I₂ = 4.235 V
Round as needed.
