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The Kentucky Derby, the first leg of horse racing’s Triple Crown, was won by a time of 122.2 s. If the race covers 2011.25 m, what was the average speed in a) m/s and b) in mi/h?
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Answer :

charlotteeich
The answer is 789.25 which you’d subtract 2011.25-122.2 I think sry if I’m wrong
LucianoCarrizo

Answer:

a) [tex]16.45 \frac{m}{s}[/tex] b) [tex]36.94 \frac{mi}{h}[/tex]

Explanation:

The average speed is given by the formula: [tex]\frac{distance}{time}[/tex]

The distance covered is 2011.25m , and the time is 122.2s.

Replacing in the formula: [tex]speed_{avg} = \frac{2011.25 m}{122.2s}[/tex]

Resulting in a) [tex]speed_{avg} = 16.45 \frac{m}{s}[/tex].

To get the result in mi/h, do the following conversion:

Knowing : 1 mi = 1603 m   and  1 h = 3600 seg

  • [tex]16.45\frac{ m}{s}*(\frac{1mi}{1603m } ) *(\frac{3600s}{1h} ) = 36.94\frac{mi}{h}[/tex]

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