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Find T1, the magnitude of the force of teTo practice Problem-Solving Strategy 11.1 Equilibrium of a Rigid Body. A horizontal uniform bar of mass 2.6 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to the end of the bar, and string 2 is attached a distance 0.7 m from the other end. A monkey of mass 1.3 kg walks from one end of the bar to the other. Find the tension T1 in string 1 at the moment that the monkey is halfway between the ends of the bar.nsion in string 1, at the moment that the monkey is halfway between the ends of the bar. Express your answer in newtons using three significant figures. View Available Hint(s)

Answer :

Answer:

[tex]T_2 = 24.95 N[/tex]

[tex]T_1 = 13.3 N[/tex]

Explanation:

As we know that total torque on the rod must be zero when monkey is at mid point of the rod

So we have

torque due to Tension at other end = torque due to weight of monkey + rod

so we will have

[tex]T_2 (3 - 0.7) = (Mg + mg)(1.5)[/tex]

here we know that

M = 2.6 kg

m = 1.3 kg

[tex]T_2(2.3) = (2.6 + 1.3)(9.81)(1.5)[/tex]

[tex]T_2 = 24.95 N[/tex]

Now similarly we can say that

[tex]T_1 + T_2 = (m + M)g[/tex]

[tex]T_1 + 24.95 = (2.6 + 1.3)(9.81)[/tex]

[tex]T_1 = 13.3 N[/tex]

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