Answer :
remember the pythagorean theorem?
this is like that
the distance is the hypotnuse
D=[tex] \sqrt{(x2-x1)^{2}+(y2-y1)^{2}} [/tex]
D=[tex] \sqrt{(8-(-3))^{2}+(-7-4)^{2}} [/tex]
D=[tex] \sqrt{(11)^{2}+(-11)^{2}} [/tex]
D=[tex] \sqrt{169+169} [/tex]
D=[tex] \sqrt{338} [/tex]
D=[tex] 11\sqrt{2} [/tex]
aprox 15.55 units
this is like that
the distance is the hypotnuse
D=[tex] \sqrt{(x2-x1)^{2}+(y2-y1)^{2}} [/tex]
D=[tex] \sqrt{(8-(-3))^{2}+(-7-4)^{2}} [/tex]
D=[tex] \sqrt{(11)^{2}+(-11)^{2}} [/tex]
D=[tex] \sqrt{169+169} [/tex]
D=[tex] \sqrt{338} [/tex]
D=[tex] 11\sqrt{2} [/tex]
aprox 15.55 units