Answer :
Answer:
(-0.6, 0.8) and (-1,0)
Step-by-step explanation:
[tex]x^2+y^2=1[/tex]
[tex]y=2x+2[/tex]
Applying y value to the first equation
[tex]x^2+(2x+2)^2=1\\\Rightarrow x^2+4x^2+4+8x=1\\\Rightarrow 5x^2+8x+3=0[/tex]
Solving the equation
[tex]x=\frac{-8+\sqrt{8^2-4\cdot \:5\cdot \:3}}{2\cdot \:5}, \frac{-8-\sqrt{8^2-4\cdot \:5\cdot \:3}}{2\cdot \:5}\\\Rightarrow x=-0.6, -1[/tex]
When x = -0.6
[tex]y=2\times -0.6+2\\\Rightarrow y=0.8[/tex]
When x = -1
[tex]y=2\times -1+2\\\Rightarrow y=0[/tex]
So, the points where the circle and line will intersect are (-0.6, 0.8) and (-1,0)
