Answer :

garydesir1

Hi

You need to start by multiply all terms by (x-2)(x+1) and cancel

x(x+1)(x-1)(x-2)=-1(x-2)(x+1)

2x²-2x+2=-x²+x+2

Now you need to subtract -x²+x+2

2x²-2x+2-(-x²+x+2)=-x²+x+2-(-x²+x+2)

3x²-3x=0

Now factorize

3x(x-1)=0

3x=0 or x-1=0

x= 0 or x=1


I hope that's help and good luck :0

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