Answer :
Answer:
h=9388.23377 meter
Explanation:
The energy is:
[tex]E= \frac{3}{2}K_BT[/tex]
the atom is coming to rest if it has no longer kinetic energy but only potential, the kinetic is converted to potential
E=mgh
to solve h:
[tex]E= \frac{3}{2}K_BT[/tex] = mgh
now putting the values
(3×295×1.3806503×10^-23)/2=39.948×(9.8×1.660538782)×10^(−27)×h
6.10937758 × 10^-21=6.50748344 ×10^(-25)×h
then h=9388.23377 meter
Atom Argon would high up 9403.761 m before coming to rest
Further explanation
Energy is the ability to do work
Energy because its motion is expressed as Kinetic energy (KE) which can be formulated as:
[tex] \large {\boxed {\bold {KE = \frac {1} {2} mv ^ 2}}} [/tex]
So for two objects that have the same speed, the greater the mass of the object, the greater the kinetic energy
Whereas for a stationary object it has kinetic energy = 0
While the energy produced from its position is called potential energy (PE)
which can be formulated as:
PE = m. g. h ⇒ gravitational potential energy
The sum of kinetic and potential energy is called mechanical energy
ME = KE + PE
The position of the object when near the surface PE = 0
Because objects (argon atoms) have kinetic energy equal to the average translational kinetic energy, then :
[tex]\rm KE=\dfrac{3}{2}kT[/tex]
K = average kinetic energy per molecule of gas (J)
k = Boltzmann's constant (1.38.10⁻²³ J / K)
T = temperature (K)
So, near the surface :
ME = KE
ME = 3/2 kT
ME = 3/2 .1.38.10⁻²³. 295
ME = 6.11.10⁻²¹
atomic mass of Argon = 39,948 u
because 1 u = 1.66.10⁻²⁷ kg, the Argon mass:
= 39,948.1.66.10⁻²⁷
= 6.63.10⁻²⁶ kg
before coming to rest: KE = 0, because ME = constant then:
ME = PE
6.11.10⁻²¹ = m. g. h (g = 9.8 m / s²)
6.11.10⁻²¹ = 6.63.10⁻²⁶. 9.8. h
[tex]\rm h=\dfrac{6.11.10^{-21}}{6.63.10^{-26}.9.8}\\\\h=9403.761~m[/tex]
Learn more
The kinetic energy of the vehicle
https://brainly.com/question/13264958
law of motion
brainly.com/question/75210
displacement of A skateboarder
brainly.com/question/1581159