Answer :

Answer:

3 x − 1 −   1/ − 3 x + 1

Step-by-step explanation:

Step-by-step explanation:

The first step is to setup the division problem

[tex]3x - 1 \sqrt{9 {x}^{2} } - 6x + 2[/tex]

Next we divide

[tex]9 {x}^{2} \div 3x = 3x[/tex]

So now we have to multiply 3x by 3x and -1 by 3x

[tex]3x \times 3x = 9 {x}^{2} \\ - 1 \times 3x = - 3x[/tex]

Then

[tex] \: \: \: \: 9 {x}^{2} - 9 {x}^{2} = 0[/tex]

[tex] - 6x + 3x = - 3x[/tex]

Now we divide

[tex] - 3x \div 3x = - 1[/tex]

Now multiply

[tex] - 1 \times - 1 = 1[/tex]

Now we

[tex] - 3x + 3x = 0 \\ 2 - 1 = 1[/tex]

So the answer is

3x-1 Remains 1/3x-1

[tex]3x - 1 + \: \frac {1}{3x - 1} [/tex]

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